140 Ib ভরের একজন লোক দৌড়াইয়া 3.8 sec এ 11 ft খাড়া পথ অতিক্রম করে উপর তলায় উঠল, তার ব্যয়িত ক্ষমতা কত?
Created: 2 years ago |
Updated: 1 year ago
best des
we know that, p = w / t
Here w = m×g×h
m=140 lb =( 140×0.454) kg = 63.5 Kg
g= 9.8 m/s2
h= 11 ft=3.35 m
So, w = 63.5×9.8×3.35=2086.705 kg/ms2 = 2084.705 N
Now, P= 2086.705 /3.8 W = 549.125 W
Hence, p= 549.125/746 HP =0.7369 HP
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